CSIR UGC NET December 2024 Exam Dates and Intimation Slip has been Out. The Exam will be held from February 28 to March 02, 2025. Check Course wise Exam Shifts and Timing in table below.
CSIR UGC NET 2024 December Exam Shift and Timing
| Exam Date | Subject and Exam Shift | Exam Shift and Timing |
| February 28, 2025 | Mathematical SciencesEarth, Atmospheric, Ocean and Planetary Sciences | Exam Shift – Shift 1 Exam Timing – 9 am to 12 noon |
| Chemical Sciences | Exam Shift – Shift 2 Exam Timing – 3 pm to 6 pm | |
| March 01, 2025 | Life Sciences | Exam Shift – Shift 1 Exam Timing – 9 am to 12 om |
| Life Sciences | Exam Shift – Shift 2 Exam Timing – 3 pm to 6 pm | |
| March 02, 2025 | Physical Sciences | Exam Shift – Shift 1 Exam Timing – 9 am to 12 pm |
The Council of Scientific and Industrial Research (CSIR) has released notification for online registration of CSIR UGC NET December 2024. The Online Registration process examination has been started on December 09, 2024 and the last date of online registration is December 30, 2024. The CSIR UGC NET is a national-level examination conducted to determine the eligibility of candidates for Junior Research Fellowship (JRF) and Lectureship (LS) in Indian universities and colleges.
CSIR UGC NET 2024: Important Dates
| EVENTS | DATES |
| Online registration Start dates | December 09, 2024 |
| Last date of online registration | |
| Last Date of Fee Payment | |
| Correction Window | January 04 to 05, 2025 (till 11:50 pm) |
| Exam Dates | February 28 and March 01, 02, 2025 |
CSIR UGC NET 2024: Overview
| OVERVIEW | DETAILS |
| Exam Name and Year | CSIR UGC NET December 2024 |
| Full Name | Council of scientific and Industrial Research (CSIR) |
| Conducted Authority | NTA |
| Pattern Of Exam | Objective Type |
| Language | English and Hindi |
| Mode of Exam | CBT Mode (Pen & Paper Based) Official Website |
| Number of Papers | 5-Papers: Chemical Sciences Earth, Atmospheric, Ocean and Planetary Sciences Life Sciences Mathematical Sciences Physical Sciences |
| Official Website | https://csirnet.nta.ac.in |
CSIR UGC NET 2024: Eligibility Criteria
To be eligible for the CSIR UGC NET December 2024 examination, candidates must meet the following criteria:
| Educational Qualification | Age Criteria |
| Degree in B. Pharma/ B. E. / B. Tech. / MSC/ MBBS integrated BS-MS/ MS-4 years or degree equivalent. (with 55% score). If Candidates are pursuing last year in MSC can apply. But you must have 10+2+3. | 28 years (as on January 1, 2025) for JRF, while there is no upper age limit for LS |
CSIR UGC NET 2024: Educational Qualifications
- For Life Science – Degree in Life science (Completed degree).
- Chemical Science – BS/ B. Tech./ M. SC or Equivalent Qualification in the chemical science field only.
- Earth Science – B. Pharma/ B.E. / B. Tech./ M. Sc. Integrated BS-MS/ MS-4 years in Earth science.
- Mathematics – BSC/ B. Pharma/ B. E. / B. Tech integrated BS-MS / MS 4 years./ Equivalent degree in mathematics.
- Physical Science – Valid Degree in M. SC. Physics or BS-MS in Physics or equivalent degree.
CSIR UGC NET 2024: Exam pattern
The CSIR UGC NET December 2024 examination will consist of three parts:
- Part A: General Science and Research Aptitude
- Part B: Subject-specific questions
- Part C: Advanced subject-specific questions
Paper- 1
| Chemical Science | Part A | Part B | Part C | Total |
| Total Questions | 20 | 40 | 60 | 120 |
| Maximum No. of Questions to attempt | 15 | 35 | 25 | 75 |
| Marks for each correct answer | 2 | 2 | 04 | 200 |
| Negative Marking (25% of Negative marking for part A, B & C) | 0.5 | 0.5 | 01 | – |
Paper -2
| Earth, Atmospheric, Ocean And Planetary Sciences | Part A | Part B | Part C | Total |
| Total Questions | 20 | 50 | 80 | 150 |
| Maximum No. of Questions to attempt | 15 | 35 | 25 | 75 |
| Marks for each correct answer | 2 | 2 | 04 | 200 |
| Negative Marking (25% of Negative marking for part A & B, 33% for Part- C) | 0.5 | 0.5 | 1.32 | – |
Paper-3
| Life Sciences | Part A | Part B | Part C | Total |
| Total Questions | 20 | 50 | 75 | 145 |
| Maximum No. of Questions to attempt | 15 | 35 | 25 | 75 |
| Marks for each correct answer | 2 | 2 | 04 | 200 |
| Negative Marking (25% of Negative marking for part A, B & C) | 0.5 | 0.5 | 01 | – |
Paper -4
| Mathematical Science | Part A | Part B | Part C | Total |
| Total Questions | 20 | 40 | 60 | 120 |
| Maximum No. of Questions to attempt | 15 | 25 | 20 | 60 |
| Marks for each correct answer | 2 | 3 | 4.75 | 200 |
| Negative Marking (25% of Negative marking for part A & B, No Negative Marking for Part- C) | 0.5 | 0.75 | 0 | – |
Part -5
| Physical Sciences | Part A | Part B | Part C | Total |
| Total Questions | 20 | 25 | 30 | 75 |
| Maximum No. of Questions to attempt | 15 | 20 | 20 | 55 |
| Marks for each correct answer | 2 | 3.5 | 5 | 200 |
| Negative Marking (25% of Negative marking for part A & B, No Negative Marking for Part- C) | 0.5 | 0.875 | 1.25 | – |
CSIR UGC NET Minimum Qualifying Marks
- Minimum Qualifying marks required for passing exam for General, EWS and OBC category Candidates is 33%.
- For SC/ST and PwD is 25%.
How to apply ?
The application process for the CSIR UGC NET December 2024 examination will be online. Candidates can follow these steps to apply:
- Registration – Candidates must register themselves on the official website of CSIR.
- Filling Application Form-Candidates must fill in the application form with their personal and educational details.
- Uploading Documents – Candidates must upload their educational certificates, photograph, and signature.
- Payment of Application Fee -Candidates must pay the application fee online through the available payment options.
Application fee to apply
| Category | Application Fee |
| General candidates | Rs. 1000/- |
| OBC-NCL Candidates | Rs. 500/- |
| SC/ST/ PwD Candidats | Rs. 250/- |
